Sci.Physics.Foundations

OK, you showed me the 361 pairs of numbers which I would denote by ( N(++ | d ), d ) where d = a - b runs from 1 to 361.

Add the counts altogether and I would denote that by N(++)

I'm so glad that Fred has managed to keep this forum going. I just wanted to mention two other opportunities for interactions: QM foundations & nature of time seminar "relaxed discussions about the foundations of physics" Every other Thursday 17:00-19:00 Central Europe Time Organiser: ...

@gill1109 I really don't understand this yet. P(++ | a,b) = N(++ | a, b) / N(a, b) What is N(++ | a, b) exactly? N(++ | a, b) would be the number of trials in which Alice sees outcome "+" and Bob sees outcome "+", when Alice has setting "a" and Bob has setting "b&...

Great that this new forum is up and running! Fred, in the original formula https://sciphysicsfoundations.com/download/outcome-pairs2.png the probabilities are understood as conditional probabilities, or probabilities given a fixed experimental condition; i.e. P(++) is shorthand for P(++ | a,b), and ...