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Joy's latest paper
Posted: Thu Oct 19, 2023 1:50 pm
by FrediFizzx
I'm having trouble with your eq. (56). You have an average of the product of two discontinuous functions on the first line and two continuous functions on the second line. That has to be an impossible equality. I suspect Bell tripped you up again.
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Re: Joy's latest paper
Posted: Thu Oct 19, 2023 9:14 pm
by Joy Christian
FrediFizzx wrote: ↑Thu Oct 19, 2023 1:50 pm
I'm having trouble with your eq. (56). You have an average of the product of two discontinuous functions on the first line and two continuous functions on the second line. That has to be an impossible equality. I suspect Bell tripped you up again.
My eq. (56) is correct. The sign functions are
continuous functions of the continuous variable
s^i, which is integrated over to produce the second line of eq. (56). Only the values, +/-1, taken by the sign functions for a given occurrence of the continuous variable
s^i are discrete. That does not make the sign functions themselves "discontinuous."
There are no mathematical mistakes in any of Bell's papers. His only mistake is a deeply conceptual mistake:
https://arxiv.org/abs/2302.09519
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Re: Joy's latest paper
Posted: Sat Oct 21, 2023 1:04 pm
by FrediFizzx
Joy Christian wrote: ↑Thu Oct 19, 2023 9:14 pm
FrediFizzx wrote: ↑Thu Oct 19, 2023 1:50 pm
I'm having trouble with your eq. (56). You have an average of the product of two discontinuous functions on the first line and two continuous functions on the second line. That has to be an impossible equality. I suspect Bell tripped you up again.
My eq. (56) is correct. The sign functions are
continuous functions of the continuous variable
s^i, which is integrated over to produce the second line of eq. (56). Only the values, +/-1, taken by the sign functions for a given occurrence of the continuous variable
s^i are discrete. That does not make the sign functions themselves "discontinuous."
There are no mathematical mistakes in any of Bell's papers. His only mistake is a deeply conceptual mistake:
https://arxiv.org/abs/2302.09519
Yeah, the infinity in the integral converts the discontinuous functions to continuous. I missed that; always thinking of finite iterations.
More later.
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